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x^2-0.82x-0.35=0
a = 1; b = -0.82; c = -0.35;
Δ = b2-4ac
Δ = -0.822-4·1·(-0.35)
Δ = 2.0724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.82)-\sqrt{2.0724}}{2*1}=\frac{0.82-\sqrt{2.0724}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.82)+\sqrt{2.0724}}{2*1}=\frac{0.82+\sqrt{2.0724}}{2} $
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